Date: Fri Apr 13 19:09:18 2007

Author: Bernard Cleyet

Subject: Re: [Phys-l] pinhole camera

Post:
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My reply to the wag on PHYS-L:


I see, a Berkeleyan.

bc, thinks not falsifiable.

Herb Gottlieb wrote:

>
>On Fri, 13 Apr 2007 14:38:18 -0400 "Robert Cohen"
> writes:
>
>
>> <>My first reaction is to agree with Michael. If you remove the
>> screen
>> and look at the pinhole, you see the object (just a very small piece
>> of
>> it).
>>
>> On the other hand, once you place the screen at a particular
>> location,
>> you produce an image there. By diffuse scattering, the rays
>> reflecting
>> off the screen are indeed (to a very close approximation) diverging
>> from
>> a point on that screen (which makes the image "real" in my view).
>>
>> So, remove the screen - no image. With the screen, image.
>>
>> With a lens, however, the image is there > regardless of whether the
>> screen is there
>> or not.
>
>
>*** It certainly sounds reasonable ....but just how can you be sure that
>the image is there when you remove the screen?????
>
>
>
>

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My reply to the wag on PHYS-L:


=C2=A0I see, a Berkeleya=
n.

bc,=C2=A0 thinks not falsifiable.

Herb Gottlieb wrote:

=20
On Fri, 13 Apr 2007 14:38:18 -0400 "Robert Cohen"
edu> writes:

<>My first reaction is to agree with
Michael. If you remove the
screen
and look at the pinhole, you see the object (just a very small piece =

of
it).

On the other hand, once you place the screen at a particular
location,
you produce an image there. By diffuse scattering, the rays
reflecting
off the screen are indeed (to a very close approximation) diverging
from
a point on that screen (which makes the image "real" in my view).

So, remove the screen - no image. With the screen, image.

With a lens, however, the image is there > regardless of whether the
screen is there
or not.


*** It certainly sounds reasonable ....but just how can you be sure that
the image is there when you remove the screen?????





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